What is the net ionic equation for HBr(aq)+Ca(OH)2(aq)→?
To find the net ionic equation for the given reaction, HBr(aq) + Ca(OH)2(aq), we need to first start with the balanced chemical equation.
The balanced chemical equation for the reaction is:
2HBr(aq) + Ca(OH)2(aq) → CaBr2(aq) + 2H2O(l)
To write the net ionic equation, we need to identify the spectator ions. These are the ions that appear on both sides of the equation and do not participate in the actual reaction.
In this case, the spectator ions are Ca2+ and 2Br-. The net ionic equation will only include the species that undergo a chemical change.
Therefore, the net ionic equation for the reaction is:
2H+ (aq) + 2OH- (aq) → 2H2O (l)
In this equation, we have removed the spectator ions (Ca2+ and 2Br-) and focused only on the species that are involved in the reaction.
Please note that the charges of the ions are not written in the net ionic equation, as they are already known based on the balanced chemical equation.
To write the net ionic equation for the reaction between HBr(aq) and Ca(OH)2(aq), we first need to write the balanced molecular equation.
The balanced molecular equation is:
2HBr(aq) + Ca(OH)2(aq) -> CaBr2(aq) + 2H2O(l)
Next, we need to consider the state of each compound.
HBr(aq) is a strong acid, so it is completely ionized in water to form H+ and Br- ions.
Ca(OH)2(aq) is a strong base and is also completely ionized in water to form Ca2+ and 2OH- ions.
CaBr2 is a soluble salt and it dissociates into Ca2+ and 2Br- ions when dissolved in water.
H2O is a liquid and does not dissociate.
Now, we can write the net ionic equation by removing the spectator ions, which are the ions that appear on both sides of the equation unchanged.
The net ionic equation is:
2H+(aq) + 2OH-(aq) -> 2H2O(l)
Therefore, the net ionic equation for the reaction between HBr(aq) and Ca(OH)2(aq) is 2H+(aq) + 2OH-(aq) -> 2H2O(l).