The Rankine temperature scale assigns a numerical value of exactly 491.67 R to the triple point of water. The ratio of two temperatures is defined as the limiting ratio, as PTP → 0, of the corresponding pressures of a gas kept at constant volume.
(a) Find the best experimental value of the normal boiling point of water on this scale.
(b) Find the temperature interval between the freezing point and the boiling point.
To find the best experimental value of the normal boiling point of water on the Rankine temperature scale, we need to convert the given value of the triple point of water in Rankine (R) to the normal boiling point of water in Rankine.
(a) The normal boiling point of water on the Rankine scale can be found by converting the triple point value of 491.67 R to the normal boiling point value.
The best experimental value of the normal boiling point of water can be determined using known conversion formulas. On the Rankine scale, the freezing point of water is assigned a value of exactly 491.67 R.
Therefore, to find the normal boiling point, we need to find the difference between the triple point and freezing point.
Normal boiling point = Triple point - Freezing point
Normal boiling point = 491.67 R - 491.67 R
Normal boiling point = 0 R
Hence, the best experimental value of the normal boiling point of water on the Rankine scale is 0 R.
(b) To find the temperature interval between the freezing point and the boiling point on the Rankine scale, we need to subtract the freezing point temperature from the boiling point temperature.
Since we found that the normal boiling point is 0 R and the freezing point is 491.67 R, we can calculate the temperature interval:
Temperature interval = Boiling point - Freezing point
Temperature interval = 0 R - 491.67 R
Temperature interval = -491.67 R
Therefore, the temperature interval between the freezing point and the boiling point on the Rankine scale is -491.67 R.