A ship travels in a southerly direction at 250km/h .A man walks at a velocity of 10m/s^-1 from the back of ship to the front of the ship .Determine the man's resultant velocity.
10 m/s x (60 seconds/min) x (60 min/hr) x (1 km/1000 m) = ? km/hr which is the man's velocity in km/hr. Add that to the velocity of the ship to get the total velocity of the man. The resultant is in km/hr in a southerly direction.
To determine the man's resultant velocity, we need to consider the velocity of the ship and the velocity of the man. Since the ship is moving in a southerly direction, and the man is walking from the back to the front of the ship, we assume that the ship's velocity and the man's velocity are in the same direction.
First, let's convert the ship's velocity from km/h to m/s to match the man's velocity:
Ship's velocity = 250 km/h = (250 km/h) * (1000 m/km) * (1 h/3600 s) = 69.44 m/s
Now, to find the resultant velocity, we will add the velocities of the ship and the man together:
Resultant velocity = Ship's velocity + Man's velocity
Resultant velocity = 69.44 m/s + 10 m/s^-1
Note: The units of velocity are in m/s, so we need to make sure both velocities have the same unit before adding them.
Since the man's velocity is already in m/s, we can add them directly:
Resultant velocity = 69.44 m/s + 10 m/s
Resultant velocity = 79.44 m/s
Therefore, the man's resultant velocity is 79.44 m/s.