Please check
Complete the following reactions
HNO3 + Sr(OH)2 -->
C6H4(OH)2 + O2 -->
my answers
2HNO3 + Sr(OH)2 --> Sr(NO3)2 + 2H2O
2C6H4(OH)2 + 13O2 --> 12CO2 + 6H2O
Zn + Ni(NO3)2-->
AlCl3 + Na2CO3-->
Al + O2 -->
NO2 -->
please check these ones too thanks
Zn + Ni(NO3)2--> Zn(NO3)2 + Ni
AlCl3 + Na2CO3--> Al2(CO3)3 + 6NaCl
Al + O2 --> 2 Al2O3
NO2 --> O2N
The first two are OK.
Zn and Ni(NO3)2 is OK
AlCl3 and Na2CO3 is not correct. Al2(CO3)2 is not known to exist. It may form as an intermediate but the final product is Al(OH3)3 and CO2.
Al + O2 is OK
NO2 to form O2N is not correct.
thanks
To check the reactions, we need to balance the chemical equations.
Let's start with the first reaction:
HNO3 + Sr(OH)2 --> Sr(NO3)2 + H2O
To balance this equation, we need to make sure that there is an equal number of atoms of each element on both sides of the equation.
For the first reaction, we have 2 hydrogen atoms on the left side (from 2HNO3) and 4 hydrogen atoms on the right side (from 2H2O). To balance the hydrogen atoms, we can put a coefficient of 2 in front of HNO3:
2HNO3 + Sr(OH)2 --> Sr(NO3)2 + 2H2O
Now let's check the second reaction:
C6H4(OH)2 + O2 --> CO2 + H2O
For this reaction, we have 12 carbon atoms on the left side (from 2C6H4(OH)2) and 1 carbon atom on the right side (from CO2). Also, we have 16 hydrogen atoms on the left side (from 2C6H4(OH)2) and 2 hydrogen atoms on the right side (from H2O). To balance the carbon and hydrogen atoms, we can put a coefficient of 6 in front of CO2 and a coefficient of 3 in front of H2O:
2C6H4(OH)2 + 13O2 --> 12CO2 + 6H2O
Now the equations are balanced.