Jody invested $4800 less in an account paying 5% simple interest than she did in an account paying 2% simple interest. At the end of the first year, the total interest from both accounts was $551. Find the amount invested in each account

just add up the interest:

(x-4800)*.05 + x*.02 = 551
Now solve for x (and x-4800)

.05 x + .02(x +4800) = 551

.07 x + 96 = 551
.07 x = 455
x = 6500
x+4800 = 11300

To find the amount invested in each account, let's set up some equations:

Let's assume that Jody invested x dollars in the account paying 2% simple interest. Therefore, she invested (x - $4800) in the account paying 5% simple interest.

The interest earned from the 2% account is (x * 0.02), and the interest earned from the 5% account is [(x - $4800) * 0.05]. The total interest earned is $551.

So, we have the equation:

(x * 0.02) + [(x - $4800) * 0.05] = $551

Now, let's solve this equation to find the value of x.

(x * 0.02) + [x * 0.05 - ($4800 * 0.05)] = $551
0.02x + 0.05x - $240 = $551
0.07x - $240 = $551

Add $240 to both sides of the equation:
0.07x = $791

Divide both sides by 0.07:
x = $791 / 0.07
x ≈ $11300

Therefore, Jody invested approximately $11,300 in the account paying 2% simple interest. Since she invested $4800 less in the account paying 5% simple interest, the amount invested in that account is $11,300 - $4800 = $6500.

So, Jody invested $11,300 in the 2% account and $6500 in the 5% account.