Two cards are drawn without replacement from a shuffled deck of 52 cards. What is the probability that the first card is a black ace and the second card is a red ace?
Select one:
a. 1/1300
b. 1/663
c. 1/2704
here's only one ace of clubs. Since the ace of clubs is black and there are 26 black cards, that leaves 25 black cards remaining for the second draw. So the probability that the first card is an ace of clubs and the second is black is:
1/52 x 25/51
there are two black aces and 2 red aces. So
P = 2/52 * 2/51 = 1/663
To find the probability of drawing a black ace followed by a red ace, we need to determine the number of favorable outcomes and the total number of possible outcomes.
The number of black aces in a deck is 2 (one spade and one club), and the number of red aces is also 2 (one heart and one diamond).
For the first card, we have 52 cards in total, so the probability of drawing a black ace is 2/52, which simplifies to 1/26.
After removing one black ace from the deck, we have 51 cards remaining. The probability of drawing a red ace on the second card is 2/51.
To find the probability of both events occurring, we multiply the probabilities of each event: (1/26) * (2/51).
This simplifies to 2/1326.
The answer is not one of the given options.