How do we solve for x?
5^(2x+1) = 6^(x-2)
My first attempt was to take the expressions of the both sides of the equation sign to one number ( as in 5^x = 5^2x) , but here I don't see a way to that too.
(2x + 1) log(5) = (x - 2) log(6)
[2 log(5)] x + log(5) = log(6) x - 2 log(6)
[2 log(5) - log(6)] x = -2 log(6) - log(5)