10x^-5 y^4 / 6y (no decimals)

i figured it was y^4 / 60xy^5 but im not sure

You have to reduce the fraction 10/6 and when the bases are the same (as in the y's) subtract the exponents...

Another way of saying that is that on the top you have yyyy while on the bottom you have only one y, so you can reduce the y's... and there would be three y's left on top.
I would be happy to check your new answer : )

nope.

10/6 x^-5 y^4/y = 5y^3 / 3x^5

Or oobleck will be happy to supply you with the correct answer : )

To simplify the expression (10x^-5 y^4) / (6y) without decimals, you need to use the properties of exponents and perform the necessary algebraic operations. Here's a step-by-step explanation:

1. Rewrite 10x^-5 as 10/x^5. This is because x^-5 is the same as 1/x^5 using the rule that x^(-n) = 1/x^n.

So now the expression becomes (10/x^5 y^4) / (6y).

2. Simplify the expression by dividing both the numerator and the denominator by the common factors.

The numerator: Divide 10 by 6, which equals 5/3. Divide x^5 by x, which gives us x^4.

The denominator: Divide y^4 by y, which results in y^3.

So the expression can be further simplified as (5/3x^4 y^3) / (y).

3. To divide fractions, you need to multiply the first fraction by the reciprocal of the second fraction.

So, multiply (5/3x^4 y^3) by 1/y.

The result is (5/3x^4 y^3) * (1/y).

4. Simplify the expression by canceling out common factors between the numerator and the denominator.

In this case, y^3/y can be simplified as y^2 since y^3 / y = y^(3-1) = y^2.

So the final simplified expression is (5/3x^4 y^2).

Therefore, your initial assumption was incorrect. The correct simplified expression is (5/3x^4 y^2) without decimals.