A bag contains 4 white, 3 blue, and 5 red marbles.
Find the probability of choosing a red marble, then a white marble if the marbles are replaced
a) 1/12
b) 5/36
c) 5/6
d) 5/12**
If you replace it, then the moves are independent
5/12 * 4/12 = 5/(3*12) = 5/36
thank you
To find the probability of choosing a red marble and then a white marble, we need to calculate the probability of each event separately and then multiply them together because both events must occur.
There are a total of 12 marbles in the bag, so the probability of choosing a red marble on the first draw is 5/12 (since there are 5 red marbles out of 12 total marbles).
Now, after replacing the first marble, the bag will still have 12 marbles. Since we replaced the marble, the probability of choosing a white marble on the second draw is also 4/12 (since there are 4 white marbles out of the 12 marbles in the bag).
To find the probability of both events occurring, we need to multiply these probabilities together:
Probability of choosing a red marble = 5/12
Probability of choosing a white marble after replacing = 4/12
Probability of choosing a red marble, then a white marble = (5/12) * (4/12) = 20/144 = 5/36
Therefore, the correct answer is option b) 5/36.