How many molecules are present in 1.5 moles of NaCl?

na =23.0 cl=35.5

23.0 +35.5 = 58.5g

1.5mol x 58.5/1mol = 85.75

85.75 is GRAMS NaCl present in 1.5 mols NaCl.

There are 6.022 molecules NaCl in 1 mol of NaCl. So there are ....... molecules in 1.5 mols NaCl.

6.02E23 molecules per mole ... Avogadro's number

To determine the number of molecules present in 1.5 moles of NaCl, you will need to use Avogadro's number, which represents the number of particles (atoms or molecules) in one mole of a substance.

Avogadro's number is approximately 6.022 x 10^23 particles/mol.

To calculate the number of molecules in 1.5 moles of NaCl, multiply the number of moles by Avogadro's number:

1.5 mol * (6.022 x 10^23 molecules/mol) = 9.033 x 10^23 molecules

To determine the number of molecules in 1.5 moles of NaCl, you need to use Avogadro's number, which states that 1 mole of any substance contains 6.022 x 10^23 particles (atoms, molecules, or ions).

Since 1.5 moles of NaCl is given, you can calculate the number of molecules using the following steps:

1. Determine the molar mass of NaCl:
The molar mass of NaCl is the sum of the atomic masses of sodium (Na) and chlorine (Cl). According to the given information, Na has a mass of 23.0 g/mol, and Cl has a mass of 35.5 g/mol.
The total molar mass is: 23.0 g/mol + 35.5 g/mol = 58.5 g/mol.

2. Calculate the number of grams of NaCl:
Multiply the number of moles of NaCl (1.5 mol) by its molar mass (58.5 g/mol) to get the number of grams: 1.5 mol x 58.5 g/mol = 87.75 g.

3. Convert grams to number of molecules:
To convert grams to the number of molecules, you need to use the concept of the mole, which is the amount of substance that contains Avogadro's number of particles.
Divide the number of grams (87.75 g) by the molar mass (58.5 g/mol) to get the number of moles: 87.75 g / 58.5 g/mol ≈ 1.5 moles.

4. Determine the number of molecules:
Multiply the number of moles (1.5 moles) by Avogadro's number (6.022 x 10^23 molecules/mol) to get the number of molecules: 1.5 moles x 6.022 x 10^23 molecules/mol ≈ 9.033 x 10^23 molecules.

Therefore, there are approximately 9.033 x 10^23 molecules present in 1.5 moles of NaCl.