John is pushing a wheelbarrow filled with sand on a building site and its content is 30 Kg.When he applies a force of 20 N,the wheelbarrow moves forward at a constant speed.
What is the magnitude of friction between the wheels and the ground?Explain your answer.(20 N)
It 20N it because the object is directly propotional to the gravitational force
To find the magnitude of friction between the wheels and the ground, we need to consider the forces acting on the wheelbarrow.
First, let's consider the forces in the horizontal direction. We have the force applied by John, which is 20 N, acting in the forward direction. We also have the force of friction opposing the motion of the wheelbarrow.
Since the wheelbarrow is moving at a constant speed, the net force in the horizontal direction is zero. This means that the force of friction must be equal in magnitude to the force applied by John, but in the opposite direction.
Therefore, the magnitude of friction between the wheels and the ground is also 20 N. The wheelbarrow is experiencing a friction force of 20 N in the opposite direction to the applied force, which allows it to move at a constant speed on the building site.
To find the magnitude of friction between the wheels of the wheelbarrow and the ground, we need to use the relationship between force, friction, and weight.
Friction is a force that opposes the relative motion between two surfaces in contact. It can be calculated using the formula F_friction = μ * F_normal, where F_friction is the friction force, μ is the coefficient of friction, and F_normal is the normal force.
In this case, the normal force is equal to the weight of the wheelbarrow and its contents. The weight can be calculated using the formula F_weight = m * g, where F_weight is the weight, m is the mass, and g is the acceleration due to gravity (approximately 9.8 m/s^2).
Given that the mass of the wheelbarrow's content is 30 Kg, the weight is F_weight = 30 Kg * 9.8 m/s^2 = 294 N.
When the wheelbarrow is moving at a constant speed, the applied force is equal to the force of friction because there is no net force acting on the wheelbarrow. Therefore, the magnitude of friction is equal to the applied force, which is 20 N in this case.
So, the magnitude of friction between the wheels and the ground is 20 N.