in a nonagon 6 of the angles are equal,and
each of the other three is 33 more than each of the 6 angles..find the angles
whats your answers
this has already been answered for you, but why not again?
6x + 3(x+33) = (9-2)*180
To find the angles of a nonagon (a polygon with nine sides), we can start by finding the value of the six equal angles. Let's call this angle "x".
We are given that there are six equal angles, so we can represent them as follows:
x, x, x, x, x, x
We are also given that each of the remaining three angles is 33 degrees more than each of the equal angles. So, we can represent the other three angles as follows:
x + 33, x + 33, x + 33
Since the sum of the interior angles of any polygon is (n-2) * 180 degrees (where n is the number of sides), we can set up an equation to solve for x:
Total sum of interior angles = (n-2) * 180
Sum of angles in a nonagon = 9 * 180 = 1620
Equation:
6x + 3(x + 33) = 1620
Now, we can solve this equation to find the value of x:
6x + 3x + 99 = 1620
9x = 1620 - 99
9x = 1521
x = 1521 / 9
x = 169
Now that we have the value of x, we can substitute it back into the equation to find the remaining angles:
x + 33 = 169 + 33 = 202
Therefore, the six equal angles are 169 degrees each, and the other three angles are 202 degrees each.