How do you integrate sin√x ?
Let u = √x
du = 1/(2√x) dx
so, dx = 2√x du = 2u du
Thus,
sin√x = 2u sinu du
Now you can use integration by parts on that.
du = 1/(2√x) dx
so, dx = 2√x du = 2u du
Thus,
sin√x = 2u sinu du
Now you can use integration by parts on that.