if a ball that is freely falling has a change of velocity of 19.6 meters after 2 seconds what is its velocity later
t=19.6/2
v=5 * 9.8
=49 m/s
To determine the velocity of the ball later, we need to know the downward acceleration due to gravity. On Earth, this value is approximately 9.8 meters per second squared (m/s^2).
Since the ball is freely falling, its velocity initially is 0. After 2 seconds, the change in velocity is 19.6 meters per second (m/s). We can use this information to find the acceleration of the ball:
Acceleration = Change in velocity / Time
Acceleration = 19.6 m/s / 2 s
Acceleration = 9.8 m/s^2
Since the acceleration is equal to the acceleration due to gravity, we can conclude that the ball is in free fall.
Now that we know the acceleration, we can determine the velocity of the ball later. The velocity of a freely falling object increases by about 9.8 m/s for every second it falls.
So, if 2 seconds have passed and the initial velocity was 0, we can calculate the velocity after a certain time using the formula:
Velocity = Initial velocity + (acceleration * time)
In this case, since the ball was falling freely, the initial velocity was 0:
Velocity = 0 + (9.8 m/s^2 * time)
By substituting the desired value for time into the equation, we can find the answer.