Algebra

a small (fictional) country had a population of 2,254,000 people in the year 2000. If the population grows steadily at a rate of 3.5% each year, what is the expected population of this country in the year 2015 to the nearest 1000?

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1,183,000
To get that you will do this set up
Is %
— *. —
Of. 100

3.5 is the percentage
100 stays 100
If is 2,254,000, you know that because the word “of” is in front of the number
Is is well we don’t know

Know the set up will look like this
X. 3.5
————— * ——
2,254,000. 100

Cross multiply
3.5* 2,254,00= 7,889,000

100 *x= 100x

Now do 100/x=x

And now do 7,889,000/100= 78,890

Now multiply that number by how many years has went by then round the number to the nearest 1000
1,183,000 people in that country in 2015

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2. Sorry wrong person

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3. Since each year the population is multiplied by 1.035, after 15 years it will be (in thousands)

2254 * 1.035^15

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2. 👎

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