Algebra

a small (fictional) country had a population of 2,254,000 people in the year 2000. If the population grows steadily at a rate of 3.5% each year, what is the expected population of this country in the year 2015 to the nearest 1000?

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  1. The answer will be
    1,183,000
    To get that you will do this set up
    Is %
    — *. —
    Of. 100

    3.5 is the percentage
    100 stays 100
    If is 2,254,000, you know that because the word “of” is in front of the number
    Is is well we don’t know

    Know the set up will look like this
    X. 3.5
    ————— * ——
    2,254,000. 100

    Cross multiply
    3.5* 2,254,00= 7,889,000

    100 *x= 100x

    Now do 100/x=x

    And now do 7,889,000/100= 78,890

    Now multiply that number by how many years has went by then round the number to the nearest 1000
    1,183,000 people in that country in 2015

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  2. Sorry wrong person

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  3. Since each year the population is multiplied by 1.035, after 15 years it will be (in thousands)

    2254 * 1.035^15

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