Given the function rule f(x)=x^2-3x+2, what is the output of f(-2)?
Ive been working on it for a while and can't figure this out, the answer options are
a. -8
b. 0
c. 4**
d. 12
Also, i will probably have more questions soon, I went thru and did the questions i Knew how to do but now i am trying to figure out how to do the rest.
x is just a place holder
f(x)=x^2-3x+2
so,
f(-2)=(-2)^2 -3(-2) + 2 = 4+6+2 = 12
How did you get 4?
In future problems, please show your work, so we can see where you go wrong (if you do)
To find the output of the function f(x) = x^2 - 3x + 2 when x = -2, you need to substitute -2 into the given function rule and evaluate it.
1. Start with the function rule f(x) = x^2 - 3x + 2.
2. Replace every occurrence of x in the function rule with -2.
f(-2) = (-2)^2 - 3(-2) + 2
3. Simplify the expression inside the parentheses first.
f(-2) = 4 + 6 + 2
4. Perform the additions to get the final answer.
f(-2) = 12
Therefore, the output of f(-2) is 12.