A car traveling at 25 mi/h accelerates to 48 mi/h over the first 5 seconds. It maintains that speed for the next 5 seconds, and then slows to a stop during the next 5 seconds. does anyone know because i have no clue here?
Vo = 25mi/h * 1600m/mi * 1h/3600s = 11.11 m/s.
V = 48/25 * 11.11 = 21.33 m/s.
V = Vo + a*t = 21.33.
11.11 + a*5 = 21.33,
a = 2.04 m/s^2.
V^2 = Vo^2 + 2a*d1 = (21.33)^2.
(11.11)^2 + 4.08*d1 = 455,
d1 = 81.3 m.
d2 = V*t = 21.33 * 5 = 106.7 m.
V = Vo + a*t = 0.
21.33 + a*5 = 0,
a = - 4.27 m/s^2.
V^2 = Vo^2 + 2a*d3 = 0.
(21.33)^2 + (-8.54)d3 = 0,
d3 = 53.3 m. = Stopping distance.
D = d1 + d2 + d3 = 81.3 + 106.7 + 53.3 = 241.3 m. = Total distance traveled.
wondering what the question is? If the question is how far does the car travel, the answer is easy:
Plot a graph of speed (in meters/second) vs time. You will have to convert all those silly mph speeds to m/s. Then, the area below the graph is distance (speed *time= distance). Break it up into simple geometric shapes, then get area. Area= distance.
disgusting nasty smelling Steve
To solve this problem, we can break it down into three parts: acceleration, constant speed, and deceleration.
1. Acceleration:
The car starts at 25 mi/h and accelerates to 48 mi/h over the first 5 seconds. To find the acceleration, we can use the formula:
acceleration = (final velocity - initial velocity) / time
In this case:
initial velocity = 25 mi/h
final velocity = 48 mi/h
time = 5 seconds
Substituting the values into the formula, we get:
acceleration = (48 mi/h - 25 mi/h) / 5 s
acceleration = 23 mi/h / 5 s
acceleration = 4.6 mi/h/s
So, the car's acceleration is 4.6 mi/h/s.
2. Constant speed:
The car maintains a speed of 48 mi/h for the next 5 seconds. Since the speed remains constant, the acceleration during this time is 0 mi/h/s.
3. Deceleration:
The car slows down from 48 mi/h to a stop during the next 5 seconds. To find the deceleration, we can again use the formula:
deceleration = (final velocity - initial velocity) / time
In this case:
initial velocity = 48 mi/h
final velocity = 0 mi/h
time = 5 seconds
Substituting the values, we get:
deceleration = (0 mi/h - 48 mi/h) / 5 s
deceleration = -48 mi/h / 5 s
deceleration = -9.6 mi/h/s
Note that here the deceleration is negative because it opposes the car's initial direction of motion.
So, the car's deceleration is -9.6 mi/h/s.
To summarize:
- The car accelerates at 4.6 mi/h/s for 5 seconds.
- It maintains a constant speed of 48 mi/h for the next 5 seconds.
- Finally, it decelerates at -9.6 mi/h/s for 5 seconds, coming to a stop.
I hope this helps clarify the situation!