Calculate the extension of a spring that would be produced by a 20N load by a 15N load extends the spring by 3cm?

force = (spring constant) * extension

To calculate the extension of a spring, you need to use Hooke's Law, which states that the force applied to a spring is directly proportional to the extension of the spring. The formula for Hooke's Law is:

F = k * x

Where:
F is the force applied to the spring (in newtons)
k is the spring constant (in newtons per meter)
x is the extension of the spring (in meters)

To find the extension of the spring produced by a 20N load when a 15N load extends the spring by 3cm, we can set up the following equation:

20N = k * x

Now, let's find the spring constant (k) by using the given information that a 15N load extends the spring by 3cm:

15N = k * 0.03m

To find k, divide both sides of the equation by 0.03m:

k = 15N / 0.03m
k = 500N/m

Now, substitute the value of k into our previous equation:

20N = 500N/m * x

To solve for x, divide both sides of the equation by 500N/m:

x = 20N / 500N/m
x = 0.04m

So, the extension of the spring produced by a 20N load when a 15N load extends the spring by 3cm is 0.04 meters (or 4 centimeters).

Any phisycs Teacher.

Naurin.