Math help!

What is the simplified form of;
3a^4b^-2c^3

4, -2, and 3 are powers

A:
81a^4c^3
________
b^2


B:
81a^4
________
b^2c^3



C:
3a^4
________
b^2c^3



D:
3a^4c^3
________
b^2



I looked through my lesson but couldn't find out how to do this... I think its D?

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  1. You will need the rule for negative exponents

    a^(-x) = 1/a^x

    so....
    3a^4b^-2c^3
    = 3(a^4)(1/b^2)(c^3)
    = 3 a^4 c^3 / b^2 , which matches D

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    posted by Reiny

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