An object of unknown metal has the following dimensions: 5.00cm long, 2.00cm wide, and 3.00cm tall. The mass of the block is known to be 79.5g.
#10 What is the formula for density?
1 point
D = V/m
D = m/V *
D = g/mL
D = m x V
#11 What is the volume of the object in cm^3? *
1 point
13
30.0*
10.0
300
#12 What is the density of the object in g/cm^3?
1 point
3.7
2.65
0.37*
0.377
#13 If the object was made of aluminum which has an accepted density of 2.70 g/cm^3, what is your percent error?
1 point
2.00%
1.85%
3.0%*
4.0%
#12 and #13 need work
Are the answers:
12) B
13) D
?
To answer #10, the formula for density is D = m/V, where D represents density, m represents mass, and V represents volume.
To answer #11, we can determine the volume of the object using the dimensions provided. The volume formula for a rectangular object is V = l x w x h, where V represents volume, l represents length, w represents width, and h represents height. Substituting the given values, we have V = 5.00cm x 2.00cm x 3.00cm = 30.0 cm^3.
To answer #12, we can use the density formula, D = m/V, where D represents density, m represents mass, and V represents volume. Substituting the given values, we have D = 79.5g / 30.0 cm^3 = 2.65 g/cm^3.
To answer #13, we can calculate the percent error by using the formula:
Percent Error = | (Accepted Value - Experimental Value) / Accepted Value | * 100%.
In this case, the accepted density of aluminum is 2.70 g/cm^3 and the experimental density we found is 2.65 g/cm^3.
Plugging in the values, we have Percent Error = | (2.70 g/cm^3 - 2.65 g/cm^3) / 2.70 g/cm^3 | * 100% = 3.0%.