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2.1 Two blocks of mass M kg and 2.5kg respectively are connected by a light, inextensible string. The string runs over a light, frictionless pulley ,The blocks are stationary

2.1.1 calculate the tension in a string
The coefficient of static friction between the unknown mass M and the surface of the table is 0.2.
2.1.2 Calculate the minimum value of M that'll prevent the blocks from moving

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  1. tension = 2.5 g = 2.5 * 9.81 Newtons

    0.2 M g = 2.5 g
    M = 2.5 / 0.2 = 12.5 kg

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  2. I need the answers and steps

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  3. M=2.5 /0.2=12.5 kg

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  4. No response

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  5. Fnet=ma
    T-fs=ma
    24.5-fs=M (0)
    -fs=-24.5
    :fs=24.5N

    Fs=0.2×(M)(9.8)
    24.5=1.96M
    M=24.5/1.96
    M=12.5kg

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