calculate the number of moles of magnesium chloride produced by reacting 168 grams of magnesium trioxocarbonate 4 with excess hydrochloric acid
Answer is 2m
how many grams per mole? You can then figure the number of moles involved.
What is the balanced equation for the reaction?
That will tell you the ratio of the compounds involved.
To calculate the number of moles of magnesium chloride produced, we need to use the balanced chemical equation for the reaction between magnesium trioxocarbonate 4 (magnesium carbonate) and hydrochloric acid. The balanced equation is as follows:
MgCO3 + 2HCl -> MgCl2 + H2O + CO2
From the equation, we can see that 1 mole of magnesium carbonate reacts with 2 moles of hydrochloric acid to produce 1 mole of magnesium chloride.
First, we need to determine the number of moles of magnesium trioxocarbonate 4 (MgCO3) present in 168 grams. To do this, we use the formula:
Number of moles = Mass (in grams) / Molar mass
The molar mass of magnesium trioxocarbonate 4 (MgCO3) is calculated by adding up the atomic masses of each element in the compound:
Molar mass of MgCO3 = (24.31 g/mol for Mg) + (12.01 g/mol for C) + (3 * 16.00 g/mol for O)
Molar mass of MgCO3 = 24.31 g/mol + 12.01 g/mol + 48.00 g/mol = 84.32 g/mol
Now we can calculate the number of moles of MgCO3:
Number of moles = 168 g / 84.32 g/mol
Number of moles = 1.995 moles (approximately)
Since the reaction uses magnesium trioxocarbonate 4 in a 1:1 ratio with magnesium chloride, the number of moles of magnesium chloride produced will also be approximately 1.995 moles.
Therefore, the number of moles of magnesium chloride produced by reacting 168 grams of magnesium trioxocarbonate 4 with excess hydrochloric acid is approximately 1.995 moles.