The distance between the midpoints of two metal balls,PandQ,respectively of masses 55 and 70kg ,is 80cm.

What is the gravitational force exerted by Q on P?
Thank you in advance

force=GM1M2/d^2

G=6.67e11
m1,m2 are above
d= .8

To calculate the gravitational force exerted by one object on another, you can use the formula for Newton's law of universal gravitation:

F = (G * m1 * m2) / d^2

Where:
F = Gravitational force between the two objects
G = Gravitational constant (approximately 6.6743 × 10^-11 N m^2 / kg^2)
m1 = Mass of object 1
m2 = Mass of object 2
d = Distance between the centers of the two objects

In this case, object P has a mass of 55 kg (m1) and object Q has a mass of 70 kg (m2). The distance between the midpoints of the two objects is given as 80 cm, which can be converted into meters by dividing by 100:

d = 80 cm / 100 = 0.8 meters

Now, let's substitute the given values into the formula:

F = (G * m1 * m2) / d^2
F = (6.6743 × 10^-11 N m^2 / kg^2 * 55 kg * 70 kg) / (0.8 meters)^2

Calculating this, we get:

F ≈ 6.74 x 10^-10 N

Therefore, the gravitational force exerted by Q on P is approximately 6.74 x 10^-10 Newtons.