If the difference of two consecutive numbers is 15 and the greater of them is x, then the smaller number is ?
Do you mean the Sum = 15? If so:
X = The larger #.
x-1 = Smaller #.
x + (x-1) = 15.
X = 8.
X-1 = 8 - 1 = 7.
geez - pick a couple of numbers and see what you get.
"difference" means subtract. So, the smaller is
x-15
The only problem I see here is that consecutive numbers are usually like 3,4,5,6,7,...
so I can't see how two consecutive numbers can differ by 15.
Let's solve this step-by-step.
Step 1: Let's assume the smaller number is y.
Step 2: The difference between two consecutive numbers is 15. This means that the greater number (x) minus the smaller number (y) is equal to 15: x - y = 15.
Step 3: We know that the greater number is x. Therefore, we can rewrite the equation as x - y = 15.
Step 4: Solving this equation for y, we can subtract x from both sides: -y = -x + 15.
Step 5: To isolate y, we multiply both sides of the equation by -1: y = x - 15.
Therefore, the smaller number is x - 15.
To find the smaller number, we need to understand the relationship between the two consecutive numbers and the given information.
Let's assume the two numbers are x and y, with y being the greater number.
According to the given information, the difference between the two consecutive numbers (y - x) is 15.
So, we can set up an equation based on this information:
y - x = 15
Since y is the greater number (as mentioned in the question), we can substitute y with x + 15 in the equation:
(x + 15) - x = 15
Now, if we simplify the equation, we get:
x + 15 - x = 15
The x terms cancel out, leaving us with:
15 = 15
This shows that the equation is true, which means any value of x can satisfy this equation.
In conclusion, there is no unique solution for the smaller number. It will depend on the value of x chosen.