3. 3y+5=-19-5
So far I have:
3y+5-5=-19-5
3y÷3=14÷3
I'm pretty sure I messed up at the 14÷3 part. I don't know hat to do next.
3y+5=-19-5
Combine like terms.
3y + 5 = - 24
3y = -5 - 24
3y = -29
y = -29/3 = -9 2/3
3y+5=-19-5
3y + 5 = -24
now subtract 5 from both sides
3y + 5 - 5 = -24 - 5
3y = -29
divide each term by 3
2y ÷ 3 = -29 ÷ 3
y = -29/3
To solve the equation 3y + 5 = -19 - 5, let's break it down step by step:
1. Start with the given equation: 3y + 5 = -19 - 5
2. Simplify both sides of the equation by combining like terms:
3y + 5 - 5 = -19 - 5
3y = -24
3. Divide both sides of the equation by the coefficient of y, which is 3:
3y ÷ 3 = -24 ÷ 3
This step is where you made a mistake. When you divide -24 by 3, you should get -8, not 14. The correct equation should be:
y = -8
Therefore, the solution to the equation 3y + 5 = -19 - 5 is y = -8.