Discrete Probability (Math)

A box contains 19 yellow, 29 green and 37 red jelly beans.
If 14 jelly beans are selected at random, what is the probability that 5 are yellow?

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  1. I got 19C5 * 66C5 / 85C14 = 0.0000273503, but my online hw is saying this answer's incorrect. Am I missing something?

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  2. Prob(yellow) = 19/85
    prob(not yellow) = 66/85

    Prob(your event)
    = C(14,5) (19/85)^5 (66/85)^9
    = .1146..

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  3. Yeah, I just realized my mistake, it was 66C9 for the remainder of the selections, not 66C5. Thank you though

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