Find the quotient of the quantity negative 15 times x to the 2nd power times y to the 6th power plus 50 times x to the 4th power times y to the 3rd power minus 20 times x to the 2nd power times y all over 5 times x to the 2nd Find the quotient of the quantity negative 15 times x to the 2nd power times y to the 6th power plus 50 times x to the 4th power times y to the 3rd power minus 20 times x to the 2nd power times y all over 5 times x power times y.
−3y5 + 10x2y2 − 4
−15x2y6 + 50x4y3 − 4
3y5 + 10x2y2 − 4
−3xy5 + 10x2y2 − 4
what are all those words????!!??
and why write them all twice, with a typo?
-15x^2y^6 + 50x^4y^3 - 20x^2y = 5x^2y(-3y^5+10x^2y^2-4)
I think the answer should now be clear.
To find the quotient of the given expression, we need to simplify the numerator and denominator separately, and then divide the numerator by the denominator.
Let's start by simplifying the numerator:
Numerator: -15x^2y^6 + 50x^4y^3 - 20x^2y
Next, let's simplify the denominator:
Denominator: 5x^2
Now, let's divide the simplified numerator by the simplified denominator:
(-15x^2y^6 + 50x^4y^3 - 20x^2y) / (5x^2)
To simplify further, we can divide each term in the numerator by the denominator:
(-15x^2y^6) / (5x^2) + (50x^4y^3) / (5x^2) - (20x^2y) / (5x^2)
Simplifying each fraction:
-3y^6 + 10x^2y^3 - 4y
Therefore, the quotient of the given expression is:
-3y^6 + 10x^2y^3 - 4y