math

The velocity function, in feet per second, is given for a particle moving along a straight line.
v(t) = 3t − 2, 0 ≤ t ≤ 3
Find the displacement
15/2

Find the total distance that the particle travels over the given interval
Im not sure how to do this one

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  1. displacement is ∫[0,3] v dt
    but since v < 0 at t = 2/3,
    total distance is ∫[9,2/3] v dt + ∫[2/3,3] -v dt

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  2. oops just backwards, since v < 0 until t = 2/3

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