a bullet of mass 10.0g sprites a wall with a velocity of 500m/s ,determine the work done by the wall on the bullet which penetrate 0.10m .

V^2 = Vo^2 + 2a*d = 0.

500^2 + 2a*0.1 = 0,
a = -1,25*10^6 m/s^2.

F = M*a = 1*10^-2 * 1.25*10^6 = -1.25*10^4 = -12,500 N.
Work = F*d = 12,500 * 0.1 = -1250 Joules.

Note: The negative sign means that the force opposes the bullet motion.

To determine the work done by the wall on the bullet, we need to calculate the kinetic energy of the bullet before and after it penetrates the wall. The work done on an object is equal to the change in its kinetic energy.

First, we need to calculate the initial kinetic energy of the bullet before it hits the wall. The formula for kinetic energy is given by:

Kinetic Energy = 0.5 * mass * velocity^2

Given:
Mass of the bullet (m) = 10.0 g = 0.01 kg
Velocity of the bullet (v) = 500 m/s

Initial Kinetic Energy = 0.5 * 0.01 kg * (500 m/s)^2

Next, we need to calculate the final kinetic energy of the bullet after it penetrates a distance of 0.10 m. The bullet comes to rest after penetrating the wall, so its final velocity is 0 m/s.

Final Kinetic Energy = 0.5 * mass * (final velocity)^2
= 0.5 * 0.01 kg * (0 m/s)^2

Now, to calculate the work done by the wall on the bullet, we can use the formula:

Work Done = Final Kinetic Energy - Initial Kinetic Energy

So, the work done by the wall on the bullet is:

Work Done = (0.5 * 0.01 kg * (0 m/s)^2) - (0.5 * 0.01 kg * (500 m/s)^2)

Simplifying the equation, we find:

Work Done = 0 - 0.5 * 0.01 kg * (500 m/s)^2

Now, we can calculate the numerical value for the work done by substituting the given values into the equation:

Work Done = -0.5 * 0.01 kg * (500 m/s)^2

Solving the expression:

Work Done = -0.5 * 0.01 kg * 250,000 m^2/s^2
= -1250 J

The negative sign indicates that the wall does negative work on the bullet, which means it absorbs energy from the bullet.