What are the first four terms of the sequence represented by the expression n(n-1)-4
A)-2,2,6,10
B)-3,0,3,6
C)-4,-2,2,8
D)-5,-4,-2,6
geez - just plug in the values for n:
T1: 1(1-1)-4 = -4
So clearly, the choice is C. But just to confirm:
T2: 2(2-1)-4 = -2
T3: 3(3-1)-4 = 2
...
I had tried that, but I did not get any correct answer:( Thank u, next Haha
Does anyone know the answer orrrrrr
its C
To find the first four terms of the sequence represented by the expression n(n-1)-4, we can substitute values of n and calculate the result.
Let's start by plugging in n = 1:
1(1-1)-4 = 0-4 = -4
So, the first term of the sequence is -4.
Now let's substitute n = 2:
2(2-1)-4 = 2(1)-4 = 2-4 = -2
The second term of the sequence is -2.
Next, with n = 3:
3(3-1)-4 = 3(2)-4 = 6-4 = 2
The third term of the sequence is 2.
Finally, let's calculate the fourth term for n = 4:
4(4-1)-4 = 4(3)-4 = 12-4 = 8
The fourth term of the sequence is 8.
Combining these results, the first four terms of the sequence are -4, -2, 2, 8.
So the correct answer is option C) -4, -2, 2, 8.