AT WHAT HIGHT ABOVE THE GROUND MUST A BODY OF MASS 10KG IS SITUATED IN OTHER TO HAVE POTENTIAL ENERGY EQUAL IN VALUE TO THE KINETIC ENERGY POSSED BY ANOTHER BODY OF MASS 10KG MOVING WITH A VELOCITY OF 10M/S
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K.e 1/2mv^2*petential energy
To find the height above the ground at which a body of mass 10 kg must be situated to have potential energy equal to the kinetic energy of another body of mass 10 kg moving with a velocity of 10 m/s, we can use the following steps:
First, let's find the kinetic energy of the moving body using the formula:
Kinetic Energy = (1/2) * mass * velocity^2
Given that the mass is 10 kg and the velocity is 10 m/s:
Kinetic Energy = (1/2) * 10 kg * (10 m/s)^2
= (1/2) * 10 kg * 100 m^2/s^2
= 500 J (Joules)
Now, to find the potential energy of a body at a certain height, we can use the formula:
Potential Energy = mass * gravity * height
Since both bodies have the same mass of 10 kg, we can simplify the formula to:
Potential Energy = 10 kg * gravity * height
To equate the potential energy to the kinetic energy, we set these two equal:
Potential Energy = Kinetic Energy
10 kg * gravity * height = 500 J
To find the height, we rearrange the equation:
height = 500 J / (10 kg * gravity)
The value of gravity can be taken as approximately 9.8 m/s^2.
height = 500 J / (10 kg * 9.8 m/s^2)
≈ 5.102 m
Therefore, the body of mass 10 kg must be situated at a height of approximately 5.102 meters above the ground to have potential energy equal in value to the kinetic energy possessed by the other body of mass 10 kg moving with a velocity of 10 m/s.