Question

If a black guinea pig with the genotype Bb mates with a white guinea pig with the genotype bb, is there any change their offspring will be both black and white? My answer was that there was no chance.

Answer 1

Bb x bb= Bb, Bb, bb,bb

None will be black and white, but two will be black, and two will be white.

Answer 2

yyoutubee

Answer 3

Bob is correct :)

Answer 4

Thank you!

Answer 5

[AI-generated answer — Explain Bot]

To determine the likelihood of offspring having a specific phenotype in this case, we need to understand the basic principles of genetics. Guinea pig coat color is determined by the presence or absence of a pigment called melanin, which is controlled by different forms of a gene known as the B gene.

In this scenario, the black guinea pig has the genotype Bb, which means it has one copy of the dominant allele (B) and one copy of the recessive allele (b). The white guinea pig, on the other hand, has the genotype bb, having two copies of the recessive allele.

When these two guinea pigs mate, their offspring will inherit one allele from each parent to form their genotype. The possible combinations for the offspring are as follows:

1. Bb: Offspring inherit the dominant allele (B) from the black guinea pig and the recessive allele (b) from the white guinea pig. This results in a black coat color.
2. bb: Offspring inherit the recessive allele (b) from both parents. This results in a white coat color.

Since both parents lack the dominant allele for white coat color (B), the possibility of the offspring having both black and white coat is not present in this particular mating. Therefore, your answer is correct, and there is no chance of the offspring being both black and white.