A circular hut has a diameter of 10m Find The cost of a mat covering the floor of the hut at R18/m^2
floor area = (π * d^2) / 4
multiply area by unit price
radius = 5 m
area = pi r^2 = 3.14157 * 5 * 5 square meters
cost = area * 18 R
Whatever an R is :)
To find the cost of a mat covering the floor of a circular hut, we first need to calculate the area of the floor.
The diameter of the hut is given as 10m, which means the radius (r) is half of the diameter. Therefore, the radius is 10m/2 = 5m.
The area of a circle is given by the formula A = πr^2, where A is the area and r is the radius.
Plugging in the values, we have A = π(5m)^2.
Calculating this, we get A = π(25m^2).
Now, let's find the cost of covering the floor. The cost is given as R18/m^2.
To find the total cost, we multiply the area of the floor by the cost per square meter.
Total cost = A * cost per square meter
= π(25m^2) * R18/m^2.
Calculating this, we get π(25m^2) * R18/m^2.
Note: π is a mathematical constant that approximates 3.14.
Therefore, the cost of covering the floor of the circular hut is approximately 3.14 * 25m^2 * R18/m^2, which simplifies to R1,413.
To find the cost of a mat covering the floor of the circular hut, we need to calculate the area of the floor and then multiply it by the cost per square meter.
The area of a circle can be calculated using the formula:
A = π * r^2
However, we are given the diameter of the hut, not the radius. The diameter is equal to twice the radius, so we can find the radius by dividing the diameter by 2.
Given that the diameter is 10 meters, the radius would be:
r = 10 / 2 = 5 meters
Now we can calculate the area of the floor using the radius:
A = π * (5^2)
A = π * 25
The value of π is approximately 3.14, so:
A = 3.14 * 25
A ≈ 78.5 square meters
Finally, we can find the cost of the mat by multiplying the area by the cost per square meter:
Cost = A * R18/m^2
Cost = 78.5 * R18
Cost ≈ R1413
Therefore, the cost of a mat covering the floor of the hut at R18/m^2 is approximately R1413.