Potassium tetraoxalate has the formula H2C2O4.KHC2O4.xH2O. 1.923 g of the above compound was neutralized by 22.7 mL of 1.000 M NaOH using phenolphthalein as the indicator. Calculate the value of x in the formula.
moles of NaOH: .0227*1=.0227 moles
moles of acid: .0227/2= .0113 moles
.0113=1.923/molmassacid
now for the mole mass of the acid, I get 218.2+ 18x
or doing the math.
218.2+ 18x=1.923/.0113
which leads to a nonsense answer (negative x). Sorry, I must have missed something perhaps you can use this to find an error.
x= 1/18 * (
To find the value of x in the formula H2C2O4.KHC2O4.xH2O, we need to use the information given in the question and perform some calculations.
Let's break down the chemical reaction occurring:
H2C2O4 + NaOH → Na2C2O4 + H2O
From the balanced equation, we can see that one mole of H2C2O4 reacts with two moles of NaOH. This means that 1.000 M NaOH (1.000 moles of NaOH per liter) can neutralize 1.000 moles of H2C2O4.
First, let's calculate how many moles of H2C2O4 are present in 1.923 g of the compound.
For this, we need to determine the molar mass of H2C2O4.
The molar mass of hydrogen (H) = 1 g/mol.
The molar mass of carbon (C) = 12 g/mol.
The molar mass of oxygen (O) = 16 g/mol.
The molar mass of H2C2O4 = (2 * 1) + (2 * 12) + (4 * 16) = 88 g/mol.
Using the molar mass, we can calculate the number of moles of H2C2O4:
Number of moles = mass / molar mass
Number of moles = 1.923 g / 88 g/mol ≈ 0.0219 mol.
Now, let's determine how many moles of NaOH were used to neutralize the H2C2O4.
The volume of NaOH used is given as 22.7 mL, which is equivalent to 0.0227 L.
Number of moles of NaOH = concentration × volume
Number of moles of NaOH = 1.000 M × 0.0227 L = 0.0227 mol.
From the balanced equation, we know that 1 mole of H2C2O4 reacts with 2 moles of NaOH. Therefore, for every 1 mole of H2C2O4, 2 moles of NaOH are required.
Using the mole ratio, we can calculate the number of moles of H2C2O4 that reacted:
Number of moles of H2C2O4 = (0.0227 mol NaOH) / 2 = 0.0114 mol.
Now, let's determine the number of moles of water (H2O) in the compound.
The compound is given as H2C2O4.KHC2O4.xH2O, meaning that for each mole of the compound, there are x moles of water present.
Since we know the number of moles of H2C2O4 (0.0114 mol), we can use this information to determine the number of moles of water present:
Number of moles of water = 0.0114 mol × x.
Finally, we need to convert the moles of water to grams. The molar mass of water (H2O) is 18 g/mol.
Mass of water = (Number of moles of water) × (molar mass of water)
Mass of water = 0.0114 mol × 18 g/mol.
Now, we have the mass of water present in the compound. We can compare this to the mass of the given compound (1.923 g) to find the value of x.
1.923 g = (0.0114 mol × 18 g/mol) + (mass of KHC2O4) + (mass of H2O).
Since the molar mass of KHC2O4 is 128 g/mol, we can calculate the mass of KHC2O4 using the following equation:
Mass of KHC2O4 = 1.923 g - (0.0114 mol × 18 g/mol).
Finally, we can calculate the value of x by rearranging the equation:
x = (1.923 g - (0.0114 mol × 18 g/mol)) / 18 g/mol.
Evaluating this equation will give you the value of x in the formula H2C2O4.KHC2O4.xH2O.