I need to make a reagent and the recipe says 60% hcl but how do I dilute my concentrated 37% hcl
You can not make 60% by diluting 37% , Think !
Perhaps you have it backwards?
Hello Damon, as you see I am not at all familiar with chemistry, ok i need to restore firearms serial number using a reagent comprising 60% hcl 40% distilled water I just don't know how to safely make this solution, is it as it appears meaning 60 ml of hcl with 4ml distilled water
If you start with a bottle containing 37% HCl You can not get to 60% HCl
However perhaps it means
use 60 mL of your 37% bottle and 40 mL of the pure water to make a total of 100 mL of the mix. That will result in a weaker acid than what was in the original bottle.
To dilute your concentrated 37% HCl (hydrochloric acid) to obtain a 60% HCl solution, you will need to perform a series of calculations and measurements. Here's a step-by-step guide on how to do it:
1. Determine the volume of 37% HCl solution you need for your desired 60% HCl solution. Let's say you need 500 mL of 60% HCl.
2. Calculate the amount of 37% HCl solution you will need to achieve this. The equation for dilution is:
C₁V₁ = C₂V₂
Where:
C₁ = initial concentration (37%)
V₁ = initial volume (unknown in this case)
C₂ = final concentration (60%)
V₂ = final volume (500 mL)
Rearrange the equation to solve for V₁:
V₁ = (C₂ * V₂) / C₁
V₁ = (0.60 * 500 mL) / 0.37
Calculating this gives us the volume of the 37% HCl needed.
3. Prepare the dilution by transferring the calculated volume of the 37% HCl into a container. Ensure the container is suitable for handling strong acids, such as glass or polypropylene.
4. Add distilled water to the container slowly while stirring until the final volume (V₂) of 500 mL is reached.
5. Mix the solution thoroughly to ensure uniformity. Use appropriate personal protective equipment, such as gloves and safety goggles, as hydrochloric acid is corrosive.
By following these steps, you should be able to dilute your concentrated 37% HCl to obtain a 60% HCl solution.