a 2m crowbar is used to lift a load of 300kg. what force must be applied to one end of the crowbar when a stump acting at the fulcrum is placed under the crowbar 0.5m away from the end on which the load rests? neglect the weight of the crowbar
the weight (force) of the load is ... 300 kg * g
the distance from the fulcrum to the lifting force is
... three times the distance from the fulcrum to the load
so the lifting force is at least 1/3 of the weight of the load
A 2m crowbar is employed to lift a load of 300kg. what force must be applied to one end of the crowbar when a stump acting. as a fulcrum is placed under a crowbar 0.5m away from the end on which the load rests? neglect the weight of the
Length of crowbar=2m
Load=300
Effort=?
The answer is not there
To solve this problem, we can use the principle of moments. The principle of moments states that for an object in rotational equilibrium, the sum of the clockwise moments about any point must be equal to the sum of the counterclockwise moments about the same point.
In this case, we will use the fulcrum as the point of reference. Since the crowbar is in equilibrium, the clockwise and counterclockwise moments must balance each other out.
First, let's calculate the moment caused by the load. The moment of a force is given by the product of the force and the perpendicular distance from the point of rotation (fulcrum) to the line of action of the force.
Given:
Length of the crowbar (L) = 2m
Load (m) = 300kg
Distance between load and fulcrum (d) = 0.5m
The moment caused by the load can be calculated as follows:
Moment of load = Load * Distance between load and fulcrum
= m * d
Since the load is given in kilograms, we need to convert it to newtons using the acceleration due to gravity. The standard value for acceleration due to gravity is 9.8 m/s^2.
Load (force) = m * g
= 300 kg * 9.8 m/s^2
Next, let's calculate the force that needs to be applied to one end of the crowbar.
Using the principle of moments, the clockwise moment created by the force applied at one end of the crowbar must be equal to the counterclockwise moment created by the load.
Moment of applied force = Moment of load
Force * Distance between fulcrum and force = Load * Distance between load and fulcrum
Force * (L - 0.5m) = Load * 0.5m
Substituting the given values:
Force * (2m - 0.5m) = (300 kg * 9.8 m/s^2) * 0.5m
Now we can solve for Force:
Force = ((300 kg * 9.8 m/s^2) * 0.5m) / (2m - 0.5m)
Simplifying the equation:
Force = (1470 N * 0.5m) / 1.5m
Finally, calculating the force:
Force = 735 N
Therefore, a force of 735 Newtons must be applied to one end of the crowbar when a stump acting at the fulcrum is placed 0.5m away from the end on which the load rests.
F1 = M*g = 300*9.8 = 2940 N.
F2 = ?
F1*d1 = F2*d2.
2940 * 0.5 = F2 * 1.5,
F2 = ?