|2t-3| = |2t| - |3t|
( || = Absolute Value)
I squared both sides to get...
(4t^2)-12t+9 = t^2
Factored to...
(t-1)(t-3) = 0
My book says "Empty Set" for the answer.
What am I doing wrong?
Absolute values are always positive. For any t, |3t| will be larger than |2t| . So, the right side is always negative.
The absolute value of the left side is always positive.
