If 465 cm cube of sulphur (iv) oxide can diffuse through porous partition in 30 seconds how long will (
a) an equal volume
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the solving
To calculate the time it takes for an equal volume of substance to diffuse through a porous partition, we need to use the concept of Graham's Law of Diffusion.
Graham's Law of Diffusion states that the rate of diffusion of a gas is inversely proportional to the square root of its molar mass. In other words, lighter gases diffuse faster than heavier gases.
In this case, we need to compare the diffusion rates of the two substances: sulphur (IV) oxide and the substance for which we want to find the diffusion time.
Step 1: Determine the molar mass of sulphur (IV) oxide.
The molar mass of sulphur (IV) oxide (SO2) is approximately 64 grams/mol.
Step 2: Determine the molar mass of the other substance.
Find out the molar mass of the substance for which we want to find the diffusion time.
Step 3: Calculate the ratio of the molar masses.
Divide the molar mass of SO2 by the molar mass of the other substance to get the ratio.
Step 4: Calculate the square root of the ratio.
Take the square root of the ratio obtained in step 3.
Step 5: Calculate the diffusion time.
Since the rate of diffusion is inversely proportional to the square root of the molar mass, we can set up the following equation:
t1/t2 = √(M2/M1)
Where:
t1 = time for the first substance to diffuse
t2 = time for the second substance to diffuse
M1 = molar mass of the first substance
M2 = molar mass of the second substance
Solving for t2 (time for the second substance to diffuse):
t2 = t1 * √(M1/M2)
By substituting the known values (t1 = 30 seconds and M1 = 64 grams/mol) along with the calculated square root of the ratio (step 4), we can find the diffusion time for an equal volume of the other substance.