Find the average kinetic energy of a 70 kg runner who covers 400 m in 45s?
KE = 1/2 mv^2
v = 400m/45s = 80/9 m/s
now just plug and chug
To find the average kinetic energy of a runner, we need to use the formula:
Average Kinetic Energy = 0.5 * mass * velocity^2
1. First, let's calculate the velocity of the runner.
velocity = distance / time
velocity = 400 m / 45 s
velocity = 8.89 m/s
2. Now, we can substitute the values into the formula:
Average Kinetic Energy = 0.5 * 70 kg * (8.89 m/s)^2
Average Kinetic Energy = 0.5 * 70 kg * 79.0321 m^2/s^2
Average Kinetic Energy = 2765.4235 J
Therefore, the average kinetic energy of the 70 kg runner who covers a distance of 400 m in 45 seconds is approximately 2765.4235 Joules.
To find the average kinetic energy of a runner, we need to use the formula:
Average kinetic energy = (1/2) * mass * velocity^2
First, let's calculate the velocity of the runner. We can use the formula:
Velocity = distance / time
In this case, the distance covered is 400 m and the time taken is 45 s. Plugging these values into the formula:
Velocity = 400 m / 45 s = 8.89 m/s (rounded to two decimal places)
Now that we have the velocity, we can calculate the average kinetic energy. Plugging the mass of the runner (70 kg) and the velocity (8.89 m/s) into the formula:
Average kinetic energy = (1/2) * 70 kg * (8.89 m/s)^2
Average kinetic energy = (1/2) * 70 kg * 78.92 m^2/s^2
Average kinetic energy = 2754.2 Joules (rounded to one decimal place)
Therefore, the average kinetic energy of the 70 kg runner who covers 400 m in 45 s is approximately 2754.2 Joules.