math

What two positive consecutive integers have a product of 72?

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  1. a = first mumber

    b = second number

    b = a + 1

    a ∙ b = 72

    a ∙ ( a + 1 ) = 72

    a² + a = 72

    a² + a - 72 = 0

    The solutions are:

    a = - 9 and 8

    For a = - 9

    b = a + 1 = - 9 + 1 = - 8

    For a = 8

    b = a + 1 = 8 + 1 = 9

    The solutions are:

    a = - 9 , b = - 8

    and

    a = 8 , b = 9

    ( - 9 ) ∙ ( - 8 ) = 72

    8 ∙ 9 = 72

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