the price of a brick today is 49 cents. this is 3 cents less than 4 times the price 20 years ago. what was the price 20 years ago?
46=4x
thats how to set up the problem to make x how much the brick was. I don't know if its right, but i tried doing it and i got
x = 11.5
I think Chopsticks misread the problem.
let P=price 20 years ago
49 cents = 4P-(3 cents)
52 cents = 4P
P=13 cents
49 - 3= 46
46/4= 11.5
x=11.5
Let P = price 20 years ago
49 = 4P - 3
Add 3 to both sides.
4P = 52
Divide both sides by 4.
P = 13 cents
Does this make it clearer? Thanks for asking.
To find the price of a brick 20 years ago, we can start by setting up an equation based on the given information.
Let's assume the price of a brick 20 years ago was "x" dollars.
According to the information given, the price of a brick today is 49 cents, which is 3 cents less than 4 times the price 20 years ago. Mathematically, this can be represented as:
49 cents = 4x - 3 cents
To solve for "x," let's isolate it by adding 3 cents to both sides:
49 cents + 3 cents = 4x - 3 cents + 3 cents
52 cents = 4x
Next, divide both sides of the equation by 4 to solve for "x":
52 cents / 4 = 4x / 4
13 cents = x
Therefore, the price of a brick 20 years ago was 13 cents.