The pressure, p, of a gas varies inversely with its volume, v. Pressure is measured in units of pa. Suppose that a particular amount of a gas is initially at a pressure of 126 pa at a volume of 52L. If the volume is expanded to 168L, what will the new pressure be?
Yes, if at constant temperature though.
p V = n R T
R is a constant
if T and n are constant then
p * V = constant call it k
p = k/V
126 = k/ 52
so
k = 52 * 126
then we expand it
p = k/168
p = 52 * 126 / 168
More questions should be answered
To solve this problem, we need to use the inverse variation formula, which states that when two variables, p and v, vary inversely, their product is a constant:
p * v = k
where p is the pressure, v is the volume, and k is the constant.
In this case, we have the initial pressure (p1) of 126 pa and volume (v1) of 52L. We want to find the new pressure (p2) when the volume (v2) is expanded to 168L.
Using the inverse variation formula, we can set up the following equation:
p1 * v1 = p2 * v2
Substituting the given values:
126 pa * 52L = p2 * 168L
Now we need to solve for p2:
p2 = (126 pa * 52L) / 168L
Simplifying the expression:
p2 = 6552 pa / 168L
Finally, dividing to get the new pressure:
p2 ≈ 38.93 pa
Therefore, the new pressure will be approximately 38.93 pa when the volume is expanded to 168L.