If term 3=15/16, term6= 5/18 and the last term is 40/729, find the number of terms in the sequence if the sequence is geometric

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asked by Linda
  1. there are 3 ratios between 15/16 and 5/18 ... (15/16) * r^3 = 5/18
    ... r = [(5/18) / (15/16)]^(1/3)

    to find the number of terms (n) ... (15/16) * r^(n-3) = 40/729
    ... n-3 = log[(40/729) / (15/16)] / log(r)

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    posted by R_scott

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