The kinetic energy of a bullet fired from a gun is 40joules,if the mass of the bullet in 0.1kg calculate the initial speed of the bullet.

I don't know the answer to it.

KE = 1/2 mv^2

so, plug in your numbers and find v

80

The work is good

To calculate the initial speed of the bullet, we can use the formula for kinetic energy:

Kinetic Energy (KE) = (1/2) * mass * velocity^2

Given that the kinetic energy of the bullet is 40 joules and the mass of the bullet is 0.1 kg, we can rearrange the formula to solve for velocity:

KE = (1/2) * mass * velocity^2

Rearranging the formula, we have:

velocity^2 = (2 * KE) / mass

Substituting the given values, we get:

velocity^2 = (2 * 40 joules) / 0.1 kg

Simplifying the equation, we have:

velocity^2 = 800 joules / 0.1 kg

velocity^2 = 8000 m^2/s^2

To find the velocity, we take the square root of both sides:

velocity = √(8000 m^2/s^2)

velocity ≈ 89.44 m/s

Therefore, the initial speed of the bullet is approximately 89.44 m/s.