3. What is a quick way to tell other 8th graders how to tell if an equation will have one solution, no solution, or infinite solutions? Explain how you know and why the equation will have the solution(s) that it does.

Help.

ms sue? anybody!

To determine if an equation will have one solution, no solution, or infinite solutions, you can follow these steps:

1. Identify the type of equation: Determine if the equation is linear or non-linear. Linear equations involve variables raised to the power of 1 (e.g., 2x + 3 = 7), while non-linear equations involve variables raised to powers other than 1 (e.g., x^2 + 3x - 2 = 0).

2. Solve linear equations: For linear equations, solve for the variable using standard algebraic techniques such as isolating the variable or using the distributive property. If you reach a point where the variable cancels out and you end up with a true statement (e.g., 3 = 3), then the equation has one solution.

3. Check for contradictions: If you reach a point where the variable cancels out, but you end up with a false statement (e.g., 3 = 4), then the equation has no solution. This means the equation represents an inconsistent relationship between the variables.

4. Identify special cases: If you end up with a true statement like "0 = 0" when solving a linear equation, this indicates that the equation has infinitely many solutions. This usually happens when the equation is an identity, meaning both sides of the equation are equivalent for any value of the variable.

5. Solve non-linear equations: For non-linear equations, the process is more complex and often requires techniques specific to each equation type. These techniques may include factoring, completing the square, or using the quadratic formula. It is crucial to understand the specific equation type and follow the corresponding solution method.

It's important to note that these steps should serve as a general guide for determining the number of solutions an equation may have. However, there may be exceptional cases where additional methods are necessary to find solutions accurately. Always consult your teacher or textbook for specific instructions when encountering complex equations.

Sorry -- I don't know.

If after simplifying you end up with an x term , you will have one unique solution

e.g. 3x + 9 = 24
3x = 15
x = 5

If after simplifying your x terms drops out and you end up with a true statement,
your equation will have an infinite number of solutions.
e.g. 4x + 6 = 2(2x+3)
4x + 6 = 4x + 6
0 = 0 , true, so infinite number of solutions

If after simplifying your x terms drops out and you end up with a FALSE statement,
your equation will have NO solution.
e.g. 2x+4 = 2(x+1) - 5
2x + 8 = 2x + 2 - 5
8 = -3 <------ FALSE, thus no solution