A computer software company models the profit on its latest video game using the relation: p(x) = -4x^2+20x-9, where x is the number of games produced in hundred thousands and p(x) is the profit in millions of dollars.
c) what is the profit when 500 000 games are produced?
you know what guys, you guys are useless, i need help and you never help me, i waited for so long for the help and no one answered. please don't answer any question from anonymous
yeah, yeah
sorry that no one was here to tell you to, I don't know,
substitute x=5
into the function?
Geez, did you even read what they told you?
PS
don't forget that p(x) is in millions of $$$$
To find the profit when 500,000 games are produced, we need to substitute the value of x = 5 into the profit function p(x).
Given:
p(x) = -4x^2 + 20x - 9
x = 5 (number of games produced in hundred thousands)
Replacing x with 5 in the equation p(x), we have:
p(5) = -4(5)^2 + 20(5) - 9
Simplifying this expression:
p(5) = -4(25) + 100 - 9
p(5) = -100 + 100 - 9
p(5) = -9 million dollars
Therefore, the profit when 500,000 games are produced is -9 million dollars.
To find the profit when 500,000 games are produced, we need to substitute x = 500,000 into the profit function p(x) = -4x^2 + 20x - 9.
Step 1: Start with the profit function equation: p(x) = -4x^2 + 20x - 9.
Step 2: Replace x with 500,000 in the equation: p(500,000) = -4(500,000)^2 + 20(500,000) - 9.
Step 3: Simplify the equation: p(500,000) = -4(250,000,000,000) + 10,000,000 - 9.
Step 4: Continue simplifying: p(500,000) = - 1,000,000,000,000 + 10,000,000 - 9.
Step 5: Further simplify: p(500,000) = - 999,990,000,009.
Therefore, the profit when 500,000 games are produced is approximately -999,990,000,009 million dollars.