Which equation is the standard form of −56x+14x^2=−51?

14x^2−56x+51=0
14x^2+51−56x=0
−56x+14x^2−51=0
14x^2−56x−51=0

I do believe it is A or D, is one of these correct?

−56x+14x^2=−51

add 51 to both sides
−56x+14x^2+ 51= 0
fix the order
14 x^2 - 56 x + 51 = 0

thank you so much!!!

I need help!

14x^2 + 56x + 21
how can I solve this using the distributive property getting the answer
7(2x2 + 8x + 3)?

To determine which equation is in the standard form of −56x+14x^2=−51, we need to rearrange the terms so that the equation is in the form of Ax^2 + Bx + C = 0.

Looking at the given options:
A) 14x^2−56x+51=0
D) 14x^2−56x−51=0

Among the given options, option A) is the correct answer as it rearranges the terms in the standard form. The equation is in the form of Ax^2 + Bx + C = 0, where A = 14, B = -56, and C = 51. Thus, the equation 14x^2−56x+51=0 is in standard form.