An industrial raw materials as the following composition by mass : iron = 28.1% chlorine = 35.7% and water of crystalization = 36.2%. Calculate the formula for the material given that Hydrogen is 1, oxygen is 16, chlorine is 35.5 and iron is 56.
cont.d
fe
28.1/56= 0.501
cl
35.7/35.5=1.005
h2o
36.2/18=2.011
divide the mole ratios by the smallest mole
fe=1
cl=2
h2o=4
FeCl₂.4H₂O
Assume you have 1000 grams, calculate moles of each:
Fe: 281/56=5.01
Cl: 357/35.5=10.0
H2O: 36.2/(18)=2.0
Now divide these mole (ratios) by the lowest one:
Fe: 2.5
Cl:5
H2O:1
Now multiply by the LCM to give whole number ratios
Fe5Cl10. 2H2Od
FerrousChloride diHydrate
I not giving me what I want
Sorry You mean 18/36.2 not 36.2/18 provided your previous examples.
U were told to find the empirical formula which goes thus
Fe=28.1%
Cl=35.7
Which is CH2O
SO TO FIND THE EMPIRICAL FORMULA WE HAVE,
ELEMENTS CL FE H O
REACTING
MASS
Fe= 28.1
cl = 35.7
h2o= 36.2
find the mole,
fe
28.1/ 56