# Physics

In an amusement park, there is a water slide that starts h meters above its base where people slide out 1.2 m above the surface of a pool. You may assume there is essentially no friction between a person and the slide.

a) What should be the maximum (safe) height h of the slide if the length of the pool is 3.0 m?

b) Does the mass of the person matter?

c) What should be the maximum (safe) height h if the slide is 0.6 m above the pool?

1. 👍 1
2. 👎 0
3. 👁 76
1. a person should land in the pool (as opposed to passing over it)
... their velocity is such that it allows the fall from 1.2 m before they clear the 3.0 m length

find the time to free-fall 1.2 m
... divide the time into 3.0 m to find the max safe velocity
... calculate the max safe slide height ... h = v^2 / (2 g)

mass is not used in any of the calculations

use the same technique for the 0.6 m drop

1. 👍 0
2. 👎 0
posted by R_scott
2. when dividing the time by 3.0, wouldnt the answer be in s/m, which is not the correct velocity term. And when dividing 3.0 by the time, it comes up as 6 m/s which seems a little too high. Am I wrong here?

I got 0.49 seconds for the time.

1. 👍 0
2. 👎 0
posted by Live
3. he said to divide the time into 3.0m
That is, divide the 3.0m by time, giving m/s

1. 👍 0
2. 👎 0
posted by oobleck

## Similar Questions

1. ### Physics

At an amusement park, a swimmer uses a water slide to enter the main pool. If the swimmer starts at rest, slides without friction, and descends through a vertical height of 2.28 m, what is her speed at the bottom of the slide?

asked by Kat on October 4, 2010
2. ### Physics

At an amusement park, a swimmer uses a water slide to enter the main pool. If the swimmer starts at rest, slides without friction, and descends through a vertical height of 2.41 m, what is her speed at the bottom of the slide?

asked by Randy on March 22, 2011
3. ### physics

At an amusement park, a swimmer uses a water slide to enter the main pool. If the swimmer starts at rest, slides without friction, and decends through a vertical height of 2.40 m, what is her speed at the bottom of the slide?

asked by lydia on November 24, 2008
4. ### Physics

At an amusement park, a swimmer uses a water slide to enter the main pool. The swimmer slides without friction, and descends through a vertical height of 2.89 m. Find the swimmer's speed at the bottom of the slide if she starts

asked by Greg on March 9, 2010
5. ### PHYSICS

At an amusement park, a swimmer uses a water slide to enter the main pool. The swimmer slides without friction, and descends through a vertical height of 2.98m. Find the swimmer's speed at the bottom of the slide if she starts

asked by RoCu on October 15, 2012
6. ### physics

Children slide down a frictionless water slide that ends at a height of 1.80 m above the pool. If a child starts from rest at point A and lands in the water at point B, a horizontal distance L = 2.46 m from the base of the slide,

asked by Amy on October 28, 2016
7. ### physics

Children slide down a frictionless water slide that ends at a height of 1.80 m above the pool. If a child starts from rest at point A and lands in the water at point B, a horizontal distance L = 2.43 m from the base of the slide,

asked by HELP!!! on November 30, 2012
8. ### physics

To enter the main pool at an amusement part, a swimmer uses a water slide which has a vertical height of 2.65 m. Find her speed at the bottom of the slide if she starts with an initial speed of 0.950 m/s.

asked by Jonathan on November 10, 2011
9. ### Physics

At an amusement park, a swimmer uses a water slide to enter the main pool. If the swimmer slides without friction, and descends through a vertical height of 3.01 m, and has a initial speed of 0.970 m/s, what is her speed at the

asked by kamich74 on October 30, 2014
10. ### Physics

In a water park, people walk a distance of 20 meters up an inclined ramp before getting on a water slide. If the spot from where they start sliding down is located 7 meters above the water’s surface, calculate the angle of the

asked by Adrian Watkins on March 21, 2016

More Similar Questions