Are the slopes given 1/-3 and -1/-3 of two lines, parallel, perpendicular, neither or both? I think the two slopes of two lines are both, but I'm not quite sure. May someone help me?
neither, since 1/-3 (- 1/3) ≠ -1/-3 (+ 1/3)
and (1/-3)(-1/-3) = -1/9 ≠ -1
Nice try. two lines can clearly NOT be both perpendicular and parallel!
parallel lines have the same slopes
Two slopes m1 and m2 belong to perpendicular lines only if m1 * m2 = -1
So, if you calculated your slopes correctly, the two lines are neither parallel nor perpendicular.
That means the two lines intersect at exactly one unique point.
If those videos you watched didn't explain this, they were failing to explain things well.
Ella, make an account for yourself at https://www.khanacademy.org -- it costs you nothing. This way, you can select the subjects you need help on, take quizzes, etc., and keep track of what you're learning.
Thank you, I will! I also took about a good hour on this problem, coming up with different slopes each time. The last time I found out that the slopes I put we're wrong and I now understand it! Thanks for the help both of you.
but, I thought there was more to definition of perpendicular besides some stuff intersecting and stuff..
All I need is help, I've looked at videos and all. Came to an dead end, I used the points given to come up with these slopes.
:( Could someone send me links to videos or practice problems so I could understand?
Okay thank you! I'm going to redo my calculations to see if I'm still correct, thank you! I'll let you know.
To determine whether the given slopes are parallel, perpendicular, or neither, we need to compare their values.
If two lines are parallel, their slopes are equal.
If two lines are perpendicular, the product of their slopes is -1.
Given slopes: 1/-3 and -1/-3
To determine whether the slopes are parallel, we can compare their values. Both slopes have the same value of -1/3. Since the slopes are equal, the lines are parallel.
To determine whether the slopes are perpendicular, we can check if the product of the slopes is -1/[(1)(-3)] = -1/(-3) = 1/3. Since the product is not -1, the lines are not perpendicular.
Therefore, the two lines with slopes 1/-3 and -1/-3 are parallel but not perpendicular.